Agent402 / tools / convert-cups-to-pints

cups → pints

FREE with proof-of-work · or $0.001 in USDC · GET /api/convert/cups-to-pints

Convert cups to pints (volume). Pass ?value=N.

1 cups = 0.5 pints. To convert, multiply the number of cups by 0.5. The reverse direction is pints → cups.

Common cups to pints values

cupspints
1 cups0.5 pints
2 cups1 pints
5 cups2.5 pints
10 cups5 pints
25 cups12.5 pints
100 cups50 pints
1000 cups500 pints

Input

FieldTypeDescription
value *stringNumeric value to convert

Example output

{
  "value": 1,
  "from": "cups",
  "to": "pints",
  "result": 0.5
}

Try it — see the 402 challenge (free)

curl -i "https://agent402.tools/api/convert/cups-to-pints?value=1"

The response is HTTP 402 Payment Required with exact payment requirements. Any x402 v2 client pays automatically and retries:

Paid call (JavaScript agent)

import { wrapFetchWithPayment } from "@x402/fetch";
import { x402Client } from "@x402/core/client";
import { registerExactEvmScheme } from "@x402/evm/exact/client";
import { privateKeyToAccount } from "viem/accounts";

const client = new x402Client();
registerExactEvmScheme(client, { signer: privateKeyToAccount(KEY) });
const payFetch = wrapFetchWithPayment(fetch, client);

const res = await payFetch("https://agent402.tools/api/convert/cups-to-pints?value=1");

No wallet? Pay with compute

This is a pure-CPU tool, so an agent without a wallet can pay with proof-of-work instead of USDC: fetch a challenge, solve it (16 leading zero bits), and resend with the X-Pow-Solution header.

import { createHash } from "node:crypto";
const lz = (b) => { let t = 0; for (const x of b) { if (!x) { t += 8; continue; } t += Math.clz32(x) - 24; break; } return t; };
const c = await (await fetch("https://agent402.tools/api/pow/challenge?slug=convert-cups-to-pints")).json();
let n = 0;
while (lz(createHash("sha256").update(c.challenge + ":" + n).digest()) < c.difficulty) n++;
await fetch("https://agent402.tools/api/convert/cups-to-pints", { method: "GET", headers: { "X-Pow-Solution": c.token + ":" + n } });

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